How To Make Bar Bending Schedule Of Column

This construction video tutorial to learn the detailed process how to make bar bending schedule (BBS) of column.

Details process the cutting length of stirrups below:

a = 600-(2×44) = 512mm


b = 300-(2×44) = 212mm

Cutting length = (2xa)+(2xb)+(2x10xd)-(5x2xd) – d= dia of strips = 8mm

= (2×512)+(2×212)+(2x10x8)-(5x2x8)


= 1528 mm or 1.528 mm

Number of Stirrups

Part A = 2700/100+1 = 28 Nos.

Part B = 2000/150-1 = 12 Nos x 4 = 48 Nos.

Part C = 1175/100+1 = 13 Nos x 3 = 39 Nos.

Part D = (650-30)/100+1 = 7 Nos.

Total Nos. of Stirrups = A+B+C+D = 122 Nos.

Watch the following video to learn more:

How to Make Bar Bending Schedule of Column

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