Here we discuss the rate analysis of the brick work or brick masonry in the superstructure brick size.

The standard size of a brick is 19cm by 9cm by 9cm without mortar.

The standard size of brick is increased 1cm with mortar, so 20cm by 10cm by 10cm.

**Problem**

Find the rate analysis of first class brickwork in cement mortar where the ratio is 1 to 6 in superstructure with the standard size of brick as above (19cm x 9cm x 9cm)

**Solution**

Brick Size without mortar = 19cm x 9cm x 9cm

In meters, this is 0.19m x 0.09m x 0.09 m

With mortar, the size of brick is increased by 1cm = 20cm x 10cm x 10cm

In meters, this is 0.2m x 0.1m x 0.1m

Let’s consider 10 m^{3} of volume of brickwork.

**Step 1: Quantity of Materials Calculation**

A) Volume of Brick Without Mortar = 0.19 m x 0.09 m x 0.09 m = 0.001539 = 1.539 x 10^{-3} m^{3}

B) Volume of Brick With Mortar = 0.2 x 0.1 x 0.1 = 0.002 = 2 x 10^{-3} m^{3}

C) We now need to find out the Quantity of Each Material:

**Brick quantity without wastage** = 10 divided by volume of brick with mortar = 10 / (2 x 10^{-3}) = 5000 Bricks

Add 5% for brick wastage = 5/100 x 5000 = 250 bricks**Total number of bricks including wastage** = 5250 bricks

Wet volume of mortar = 10 – 5000 x 1.539 x 10^{-3} = 2.31 m^{3}

Add 25% mortar for frog filling (brick indentations) and wastage = 25/100 x 2.31 = 0.577 m^{3}

Adding these two amounts gives us the **Total Wet Volume of the Mortar** which is 2.9 m^{3}

Next is the **Dry Volume of Mortar** which is 30% more than the above total wet volume of the mortar = 1.30 x 2.9 = 3.77 m^{3}

**Quantity of Cement** = ( 3.77 / (1 + 6) ) x 1 = 0.538 m^{3}

**Number of Bags of Cement** = quantity of cement divided by volume (Volume of 1 bag of cement = 0.035 or 35 litres) = 0.538 / 0.035 = 15.37 (so 16 bags of cement)

**Quantity of Sand** = ( 3.77 / (1 + 6) ) x 6 = 3.23 m^{3}

**Step 2: Example Cost Calculation**

Particulars |
Quantity |
Rate |
Per |
Cost |
---|---|---|---|---|

Materials, Cement, Sand, Bricks | 16 for cement, 3.23 for sand, 5250 for bricks | 350 for cement, 1350 for sand, 4500 for bricks | Kg for cement, M^{3}for sand, 1000 numbers for bricks |
5600 for cement, 4360.5 for sand, 23625 for bricks |

Total Amount | 33585.5 | |||

Labor |
||||

Head mason | ½ numbers | 600 | Per day | 300 |

Mason | 10 numbers | 500 | Per day | 5000 |

Worker A | 10 numbers | 300 | Per day | 3000 |

Worker B | 10 numbers | 250 | Per day | 2500 |

Other | 2 | 200 | Per day | 400 |

Total Amount | 11200 | |||

Total Cost (Materials + Labor) |
44785.5 |

Add 1.5% for water cost = 1.5/100 x 44785.5 = 671.8

Add 1.5% for tools and plants = 1.5/100 x 44785.5 = 671.8

Add 3% for lumpsum = 3/100 x 44785.5 = 1343.6

Add 10% for contractor’s profit = 10/100 x 44785.5 = 4478.55

Add these four to the total =** Grand Total = 51951.3**

**Rate per m ^{3} = 51951.3/10 = 5195.13**

For further information on this subject, watch the following video tutorial.