In this illustration we will calculate cement, sand, crushed stone and of course steel for given water tank.
RCC has 1:2:4 with 15 cm thickness
PCC has 1:2:4 with thickness equal to 10 cm
The slab is RCC having 1:2:4 with 10 cm thickness
And of course there is a hole and the hole is circular with diameter = 60 cm
The depth is equal to 3 cm
The steel is 1% and #4 bar will be used
Solution:
Diameter = 4 meter + 2(15 cm) + 2 (10 cm) = 4.5 m = external circle diameter
PCC work = πD2/4 * T = π (4.5)2/4 * 0.1 = 1.59 m3
Assume the base or floor as S1 and wall as S2
D2 = 4 meter + 2(15 cm) = 4.3 m
The next approach is the RCC work in wall S1 = π (D1)2/4 * T = π (4.3)2/4 * 0.15 = 2.178 m3
RCC work in wall S2 = π ((D1)2 – (D)2)/4 * d = π ((4.3)2 – (4)2)/4 * 3 = 5.867 m3
RCC work in slab = π (4.3)2/4 * 0.1 = 1.452 m3
Deduction for hole = π (0.6)2/4 * 0.1 = 0.0282 m3
RCC work in Slab – Deduction for hole = 1.423 m3 = net quantity of RCC slab
Total RCC work = 2.178 m3 + 5.867 m3 + 1.452 m3 + 1.423 m3 = 9.468 m3
Steel = 1/100 * 9.468 = 0.09468 m3 * 7850 kg/cu.m (is the unit weight of density of mild steel) = 744 kg
Total net RCC = 9.468 m3 – 0.09468 m3 = 9.373 m3
Total PCC work (1:2:4) = 1.59 m3 + 9.373 m3 = 10.963 m3
Let’s calculate cement, sand and crushed stone work
Material = ratio of material/sum of ratio * dry volume
Ratio is 1:2:4 and sum of ratio is 7
Dry volume = wet volume * 1.54
Wet volume = 20*12*0.5
Wet volume = 120 CFT
Dry volume = 120 * 1.54
Dry volume = 184.8 CFT
Cement = 1/7 * 184.8 =26.4 CFT
Cement = 26.4/1.24 = 21.12 bags
Sand = 26.4 * 2 = 52.8 cft/100 = 0.528 sacra
Bajri = 26.4 * 4 = 105.6cft/100 = 1.056 sacra
Crushed stone = 6/10 * 770 = 462 CFT
Bajri = 462/100 = 4.62 sacra
To learn the complete process, watch the following online video demonstration.
